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Molar Gas Volume Formula

Molar Gas Volume Formula:

\[ V_m = 22.4 \text{ L/mol (at STP)} \]

mol
atm
K

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1. What is Molar Gas Volume?

The molar gas volume is the volume occupied by one mole of an ideal gas at a given temperature and pressure. At standard temperature and pressure (STP: 0°C and 1 atm), one mole of any ideal gas occupies 22.4 liters.

2. How Does the Calculator Work?

The calculator uses the ideal gas law and molar volume formula:

\[ V_m = \frac{RT}{P} \] \[ V = n \times V_m \]

Where:

Explanation: At STP (273.15K, 1 atm), the molar volume is calculated as \( V_m = \frac{0.082057 \times 273.15}{1} = 22.4 \) L/mol.

3. Importance of Molar Volume Calculation

Details: Molar volume is fundamental in stoichiometric calculations for gases, determining gas densities, and converting between moles and volume in chemical reactions involving gases.

4. Using the Calculator

Tips: Enter the amount of substance in moles, pressure in atmospheres, and temperature in Kelvin. For STP conditions, use P=1 atm and T=273.15K.

5. Frequently Asked Questions (FAQ)

Q1: What is STP?
A: STP stands for Standard Temperature and Pressure, defined as 0°C (273.15K) and 1 atmosphere pressure.

Q2: Why is molar volume 22.4 L/mol at STP?
A: This value comes from the ideal gas law calculation using R=0.082057 L·atm·mol⁻¹·K⁻¹ at T=273.15K and P=1 atm.

Q3: Does molar volume change with different gases?
A: For ideal gases, molar volume is the same for all gases at the same T and P. Real gases show slight variations.

Q4: How to convert Celsius to Kelvin?
A: Kelvin = Celsius + 273.15. For example, 25°C = 298.15K.

Q5: What is the molar volume at room temperature?
A: At 25°C (298.15K) and 1 atm, molar volume is approximately 24.5 L/mol.

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